I suggest that it is (sin A)^2 + (cos A)^2 = 1
In radians. sin(1.0003) = 0.8416330376 ===================
It is ln[1+sqrt(2)] = 0.8814, approx.
sin^2 (feta) + cos^2 (feta) = 1 sin (feta) / cos (feta) = tan (feta)
angle can be defined as sin-1=O/H, cos-1=/H, or Tan-1=O/A
I suggest that it is (sin A)^2 + (cos A)^2 = 1
In radians. sin(1.0003) = 0.8416330376 ===================
It is ln[1+sqrt(2)] = 0.8814, approx.
sin^2 (feta) + cos^2 (feta) = 1 sin (feta) / cos (feta) = tan (feta)
You could try the series sin(x) = 1 - x/1! + x^3/3! - x^5/5! + ... but you would soon need a calculator. And if you're using a calculator you may as well use it to find the sine.
angle can be defined as sin-1=O/H, cos-1=/H, or Tan-1=O/A
The uses of Sin, Cos etc. in Maths is in relation to Trigonometry. Trigonometry is the study of the relationship between angles and lengths of triangles.
csc(x) = 1/sin(x) = +/- 1/sqrt(1-cos^2(x))
Using the Sine function Sin(x) = 0.5 Then x = Sin^(-1)0.5 x = 30 degrees. Sin^(-1) in the inverse function on you calculator. . It works for Sin , Cosine and Tangent of any angle.
Not true. tan(45) = 1 is a whole number. sin(0) = 0 and sin(90) = 1 are whole numbers. So the question is based on nonsense!
If you reflect a function across the line y=x, you will have a graph of the inverse. For trigonometric problems: y = sin(x) has the inverse x=sin(y) or y = sin-1(x)
Yes. 'sin2x + cos2x = 1' is one of the most basic identities in trigonometry.