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What is treated for sulfamethoxazole tmp ds tabitp?
Urinary Tract Infections
Write a program that accepts 15 different numbers and find the LCM and HCM?
/* Program to find LCM/HCF of 15 Nos in C++/ C (replace cin with scanf & cout with printf for c) */ /* Developed by - Kishore Kr. Banerjee - papillon_kish@yahoo.com */ #include <iostream.h> #include <conio.h> main() { int num[3],i,j,p,q,tmp,n1,n2,LCM,rem,flag; clrscr(); for(i=0;i<3;i=i+1) { cout<<"Enter No - "<<i+1<<"="; cin>>num[i]; } clrscr(); n1=num[0]; p=n1; for(i=1;i<3;i=i+1) { n2=num[i]; /* Finding HCF */ q=n2; if(p<q) { tmp=q; q=p; p=tmp; } while(p%q!=0) { rem=p%q; q=p; p=rem; if(p<q) { tmp=q; q=p; p=tmp; } } /*finding LCM */ LCM=1; for(j=1;n1%j==0n2%j==0;j=j+1) { if(n1%j==0) { n1=n1/j; flag=1; } if(n2%j==0) { n2=n2/j; flag=1; } if(flag==1) { LCM=LCM*j; } } LCM=LCM*n1*n2; n1=LCM; } cout<<"the LCM ="<<LCM; cout<<"the hcf ="<<q; getch(); } ----- int gcd (int a, int b) { . int tmp; . if (a<0) a= -a; . if (b<0) b= -b; . if (a<b) tmp= a, a= b, b= tmp; . while (b) { . . tmp= a%b; . . a= b; . . b= tmp; . } . return a; } int gcd_n (int n, const int *vect) { . int i, gcdtmp; . for (i=0, gcdtmp=0; i<n && gcdtmp!=1; ++i) . . gcdtmp= gcd (gcdtmp, vect[i]); . return gcdtmp; } int LCM (int a, int b) { . int d= gcd (a, b); . if (d==0) return d; . else return a/d*b; } int lcm_n (int n, const int *vect) { . int i, lcmtmp; . for (i=0, lcmtmp=1; i<n; ++i) . . lcmtmp= LCM (lcmtmp, vect[i]); . return lcmtmp; }
Write a program that asks the user to type two integers A and B and exchange the value of A and B?
// While this doesn't prompt the user for input, it does reverse the values' contents. $intA = '10'; $intB = '20'; $tmp = $intA; $intB = $intA; $intA = $tmp; print $intA; // 20 print $intB; // 10 // An even quicker way is... list($b,$a) = array($a,$b);
How does plus plus a differ from a plus plus in c language?
It's a matter of if the variable (in your case, a) is incremented before or after it is referenced. Or so says Hewlett-Packard in their HP-UX C compiler manualNow, as for how the difference matters in a practical manner, see related link below for the explanation- it can do a better explanation than I can.To quote Wikipedia (legal notice: the following text is licensed under the GNU Free Documentation License):The precedence table determines the order of binding in chained expressions, when it is not expressly specified by parentheses.For example, ++x*3 is ambiguous without some precedence rule(s). The precedence table tells us that: x is 'bound' more tightly to ++ than to *, so that whatever ++ does (now or later-see below), it does it ONLY to x (and not to x*3); it is equivalent to (++x, x*3).Similarly, with 3*x++, where though the post-fix ++ is designed to act AFTER the entire expression is evaluated, the precedence table makes it clear that ONLY x gets incremented (and NOT3*x); it is functionally equivalent to something like (tmp=3*x, x++, tmp) with tmp being a temporary value.Precedence and bindingsAbstracting the issue of precedence or binding, consider the diagram above. The compiler's job is to resolve the diagram into an expression, one in which several unary operators ( call them 3+( . ), 2*( . ), ( . )++ and ( . )[ i ] ) are competing to bind to y. The order of precedence table resolves the final sub-expression they each act upon: ( . )[ i ] acts only on y, ( . )++ acts only on y[i], 2*( . ) acts only on y[i]++ and 3+( . ) acts 'only' on 2*((y[i])++). It's important to note that WHAT sub-expression gets acted on by each operator is clear from the precedence table but WHEN each operator acts is not resolved by the precedence table; in this example, the ( . )++ operator acts only on y[i] by the precedence rules but binding levels alone do not indicate the timing of the Suffix ++ (the ( . )++ operator acts only after y[i] is evaluated in the expression).Many of the operators containing multi-character sequences are given "names" built from the operator name of each character. For example, += and -= are often called plus equal(s) and minus equal(s), instead of the more verbose "assignment by addition" and "assignment by subtraction".The binding of operators in C and C++ is specified (in the corresponding Standards) by a factored language grammar, rather than a precedence table. This creates some subtle conflicts. For example, in C, the syntax for a conditional expression is: logical-OR-expression ? expression : conditional-expressionwhile in C++ it is: logical-or-expression ? expression : assignment-expressionHence, the expression: e = a < d ? a++ : a = dis parsed differently in the two languages. In C, this expression is a syntax error, but many compilers parse it as: e = ((a < d ? a++ : a) = d)which is a semantic error, since the result of the conditional-expression (which might be a++) is not an lvalue. In C++, it is parsed as: e = (a < d ? a++ : (a = d))which is a valid expression.The precedence of the bitwise logical operators has been criticized.[1] Conceptually, & and | are arithmetic operators like + and *.The expression ​a & b 7​. This requires parentheses to be used more often than they otherwise would.
