Flatworms have a higher surface area/volume ratio compared to a cylindrical worm, this is one of the reasons for flatworms to have the structure they do.
times leagth times weith
The area of a three dementional figure is divided into lateral surface area and total surface area. The total surface area of a cylindrical box can be calculated by using the formula : 2 times pi times radius squared plus 2 times pi times radius times hight The lateral surface area can be calculated by the formula: 2 times pi times radius times height
The area of the cylindrical part of the surface is equal to the perimeter of the base multiplied by the height. The perimeter of a circle with diameter 12 is pi times the diameter; therefore, the area of the cylindrical part of the surface is 12 X 15 X pi = 5.6 X 102. (Only two significant digits are justified, since there are only two in the primary data.) Sometimes the surface area is considered to include the upper lower bases of the cylinder along with the cylindrical area. The area of a circle is pi multiplied by the square of the radius, which is half the diameter. (12/2)2 X pi = 1.1 X 102. If both bases are added to the cylindrical area, the total area is 7.8 X 102, to the justified number of significant digits.
Surface area = (2*pi*0.922)+(2*pi*0.92*2.6) = 20.347 m2 to 3 decimal places
Flatworms have a higher surface area/volume ratio compared to a cylindrical worm, this is one of the reasons for flatworms to have the structure they do.
times leagth times weith
Biggest surface area to volume ratio.
The area of a three dementional figure is divided into lateral surface area and total surface area. The total surface area of a cylindrical box can be calculated by using the formula : 2 times pi times radius squared plus 2 times pi times radius times hight The lateral surface area can be calculated by the formula: 2 times pi times radius times height
A cylindrical protist has a higher surface are to volume ratio. This is because of the physical properties of spheres (some rather complicated math proves that spheres hold the most volume for their area).
Surface area of a sphere = 4*pi*radius2 For a spherical shell, surface area = surface area of outer sphere - surface area of inner sphere = 4*pi*(outer radius)2 - 4*pi*(inner radius)2 = 4*pi*[ (outer radius)2 - (inner radius)2 ]
3πR2 + πr2
The area of the cylindrical part of the surface is equal to the perimeter of the base multiplied by the height. The perimeter of a circle with diameter 12 is pi times the diameter; therefore, the area of the cylindrical part of the surface is 12 X 15 X pi = 5.6 X 102. (Only two significant digits are justified, since there are only two in the primary data.) Sometimes the surface area is considered to include the upper lower bases of the cylinder along with the cylindrical area. The area of a circle is pi multiplied by the square of the radius, which is half the diameter. (12/2)2 X pi = 1.1 X 102. If both bases are added to the cylindrical area, the total area is 7.8 X 102, to the justified number of significant digits.
Surface area = (2*pi*0.922)+(2*pi*0.92*2.6) = 20.347 m2 to 3 decimal places
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
The electric field on the cylindrical Gaussian surface is oriented perpendicular to the surface, pointing outward or inward depending on the charge distribution inside the surface.
In cylindrical coordinates, the surface element is represented by the product of the radius and the differential angle, which is denoted as (r , dr , dtheta).