Using Euler's relation, we know that e^(i*n*pi) = cos(n*pi) + i*sin(n*pi) where n is an integer. We also know that we can rewrite 10 as e raised to a specific power, namely e^(ln(10)). So substituting this back into 10^i and then applying Euler's relation, we obtain 10^i = (e^(ln(10)))^i = (e^(i*ln(10))) = cos(ln(10)) + i*sin(ln(10)).
10^14
(-10) raised to 2 = 100
10 raised to the power of -1 is 0.1
It is ten raised to the power of a googol: 10^googol
To calculate six times ten to the negative power, multiply 6 by the value of ten raised to the negative power. For example, if the power is -3, it would be 6 times 10 to the negative third power, which equals 0.006.
10 raised by the ten power is 10000000000, also known as ten million.
10^14
0.000 000 01 is.
One ten billionth
(-10) raised to 2 = 100
10 raised to the power of -1 is 0.1
15
1000000000x1000000000 = 1,000,000,000,000,000,000In more useful terms, the answer is 10E18, or ten raised to the 18th power.
It is ten raised to the power of a googol: 10^googol
To calculate six times ten to the negative power, multiply 6 by the value of ten raised to the negative power. For example, if the power is -3, it would be 6 times 10 to the negative third power, which equals 0.006.
11 raised to the 9th power divided by 9 raised to the 90th power
A^8 or A raised to the power of 8.