The expression (3n - 3) represents a linear function where (n) is a variable. It can be factored as (3(n - 1)), indicating that for each unit increase in (n), the value of the expression increases by 3. The term can also be interpreted in various contexts, such as in sequences or algebraic equations, depending on the value assigned to (n).
2/3n3
One possible answer is: Un = (3n3 - 3n2 + 78n - 8)/560 for n = 1, 2, 3, 4.
Given any number, it is always possible to find a polynomial of degree 6 that will fit the above numbers and the additional given number.The simplest position to value rule, in polynomial form, for the above sequence isUn = (3n3 - 5n2 + 4n - 12)/2 for n = 1, 2, 3, ...and accordingly, U7 = 412.
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.
Any number of your choice. It is possible to find a quartic (order 4) polynomial that will fit the given 4 points and any other. There is only one cubic that will do the trick: Un = (-3n3 + 26n2 - 63n + 52)/2 for n = 1, 2, 3, ... and according to it U5 = 6.
2/3n3
The GCF is 3n3
6590. One possible sequence is 2472/3N3 - 14421/2N2 + 26165/6N - 1390
One possible answer is: Un = (3n3 - 3n2 + 78n - 8)/560 for n = 1, 2, 3, 4.
Given any number, it is always possible to find a polynomial of degree 6 that will fit the above numbers and the additional given number.The simplest position to value rule, in polynomial form, for the above sequence isUn = (3n3 - 5n2 + 4n - 12)/2 for n = 1, 2, 3, ...and accordingly, U7 = 412.
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.
Any number of your choice. It is possible to find a quartic (order 4) polynomial that will fit the given 4 points and any other. There is only one cubic that will do the trick: Un = (-3n3 + 26n2 - 63n + 52)/2 for n = 1, 2, 3, ... and according to it U5 = 6.
It is term.
The Tagalog term for "term" is "tuntun".
Given ANY number, it is easy to find a polynomial of order 4 such that if you use it as a position to value rule you get the four given numbers and your chosen one as the fifth. As a result, any number can be the next in the sequence. The simplest polynomial of order 3 for the above four numbers is: Un = (-3n3 + 32n2 - 57n + 34)/2 for n = 1, 2, 3, ... Accordingly, the next number is 87.
Term-to-term is -3
Answer: Short Term