Use the following formula:
an = a1 + (n - 1)d, where
a1 = the first term
n = the n th term (general term)
d = common difference (which is constant between terms)
Since we need to find the 14 th term, we can write:
a1 = 100
n = 14
d = -4
an = a1 + (n - 1)d
a14 = 100 + (14 - 1)(-4)
a14 = 100 + (13)(-4)
a14 = 100 - 52
a14 = 48
Thus, the 14 th term is 48.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is constant. For example, the sequence 2, 5, 8, 11, 14 has a common difference of 3. Another example is 10, 7, 4, 1, which has a common difference of -3. In general, an arithmetic sequence can be expressed as (a_n = a_1 + (n-1)d), where (a_1) is the first term and (d) is the common difference.
16
6
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
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It is a + 8d where a is the first term and d is the common difference.
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
6
From any term after the first, subtract the preceding term.
The common difference is 6; each number after the first equals the previous number minus 6.
6
6
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