16 can have only one square and that is 256.
The two square numbers that, when one is subtracted from the other, equal seven are 16 and 9. This is because (4^2 - 3^2 = 16 - 9 = 7). Thus, the square numbers are 16 (from (4^2)) and 9 (from (3^2)).
They are: 4*4 = 16
The two square numbers that subtract to 7 are 16 and 9. Specifically, (4^2 = 16) and (3^2 = 9), and when you subtract 9 from 16, you get 7: (16 - 9 = 7).
The two square numbers that have a difference of 9 are 25 and 16. This can be expressed as (5^2 = 25) and (4^2 = 16). The difference between them is (25 - 16 = 9).
25 - 9 = 16
They are: 4*4 = 16
The two square numbers that, when one is subtracted from the other, equal seven are 16 and 9. This is because (4^2 - 3^2 = 16 - 9 = 7). Thus, the square numbers are 16 (from (4^2)) and 9 (from (3^2)).
16 and 9
The two square numbers that subtract to 7 are 16 and 9. Specifically, (4^2 = 16) and (3^2 = 9), and when you subtract 9 from 16, you get 7: (16 - 9 = 7).
The two square numbers that have a difference of 9 are 25 and 16. This can be expressed as (5^2 = 25) and (4^2 = 16). The difference between them is (25 - 16 = 9).
52 - 32 = 16.
25 - 9 = 16
The pair of square numbers that add up to 80 is 16 and 64. Specifically, (4^2 = 16) and (8^2 = 64), since (16 + 64 = 80).
These are square numbers. 1, 4, 9, 16, 25 1 2, 2 2, 3 2, 4 2, 5 2, next number is 6 2 = 36
Let the two square numbers be ( a^2 ) and ( b^2 ), where ( a^2 - b^2 = 21 ). This can be factored as ( (a-b)(a+b) = 21 ). The pairs of factors of 21 are (1, 21) and (3, 7). Solving these gives the pairs ( (11, 10) ) or ( (5, 4) ), leading to the square numbers ( 121 ) and ( 100 ) or ( 25 ) and ( 16 ). Thus, the two square numbers can be ( 121 ) and ( 100 ) or ( 25 ) and ( 16 ).
The two square numbers that total 25 are 16 and 9. This is because 16 is (4^2) and 9 is (3^2), and when added together, they equal 25 (16 + 9 = 25).
They can be: 16 -4 = 12