494, 495, and 496. One way to figure it: Let the 3 numbers be N, N+1, and N+2.
So N + N+1 + N+2 = 3*N + 3. Set equal to 1485, and solve for N. N = 494. So the other two numbers are 495 and 496.
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8,9,10,11,12
The numbers are -8, and -7.
The numbers are 20 and 21.
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.