494, 495, and 496. One way to figure it: Let the 3 numbers be N, N+1, and N+2.
So N + N+1 + N+2 = 3*N + 3. Set equal to 1485, and solve for N. N = 494. So the other two numbers are 495 and 496.
8,9,10,11,12
The numbers are -8, and -7.
The numbers are 20 and 21.
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.
There are two consecutive even numbers. The numbers are 62 and 64.
8,9,10,11,12
The numbers are 244 and 245.
The numbers are -8, and -7.
The numbers are 20 and 21.
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
The two consecutive numbers whose factors have the same sum are 8 and 9. The factors of 8 are 1, 2, 4, and 8, and their sum is 15. The factors of 9 are 1, 3, and 9, and their sum is also 15. Therefore, 8 and 9 are the consecutive numbers whose factors have the same sum.
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.
61 & 62
417 and 418
The numbers are 87 and 89.
The numbers are 43 and 45.