1.37973 (to 5 dp)
1) 1 (5th root is 1)2) 32 (5th root is 2)3) 243 (5th root is 3)4) 1024 (5th root is 4)5) 3125 (5th root is 5)
The 5th root is 20.
The 5th root of 400 = 3.314454
The square root of (16b^5) can be calculated by taking the square root of each factor separately. The square root of (16) is (4), and the square root of (b^5) is (b^{5/2}), which can be expressed as (b^2 \sqrt{b}). Therefore, the final answer is (4b^2\sqrt{b}).
sqrt[(-50x)5] = sqrt(-312500000x5) = ± 17677.6695*x2.5 * i where i is the imaginary square root of -1.
1) 1 (5th root is 1)2) 32 (5th root is 2)3) 243 (5th root is 3)4) 1024 (5th root is 4)5) 3125 (5th root is 5)
3130
The 5th root of 31,253 = 7.92461811
The 5th root of 64 = 2.297397
The 5th root of 1024 is calculated by determining what number, when raised to the power of 5, equals 1024. Since ( 1024 = 2^{10} ), the 5th root can be expressed as ( 1024^{1/5} = (2^{10})^{1/5} = 2^{10/5} = 2^2 = 4 ). Therefore, the 5th root of 1024 is 4.
NO!!! Remember 3^(5) = 243 Hence 243^(1/5) = 3
5th_rt(0.00032) = 5th_rt(25/2555) = 5th_rt(1/55) = 1/5 = 0.2
(i)^4/5 is the same as taking the 5th root of i to the 4th power. (i)^4 = 1 and the 5th root of 1 is 1 so your answer is 1.
The 5th root is 20.
The 5th root of 400 = 3.314454
The 5th root of 95 = 2.48625
5*[sqrt(r)]5 = 27 => r = 1.9632, approx.