12=22x3 15=3x5 So the LCM of 2, 12 and 15 is 22x3x5 = 60
the prime factorization of 12 in exponents is 2 to the second power times 3
22 x 3 = 12
2 x 2 x 2 = 8 2 x 2 x 3 = 12 2 x 2 x 2 x 3 = 24, the LCM
2 x 2 x 3 = 12 2 x 2 x 2 x 2 = 16 2 x 2 x 2 x 2 x 3 = 48, the LCM
The LCM of the given two numbers is 48
They are: 12 and 360 respectively
Two or more numbers are normally needed to find the LCM
That's a lot of extra work for this problem but here goes. 3 is already prime so it doesn't really have a factor tree or prime factorization. The prime factorization of 4 is 2 x 2 which looks like this in a factor tree.42,23 and 4 have no common prime factors, so the LCM is their product, 12
12=22x3 15=3x5 So the LCM of 2, 12 and 15 is 22x3x5 = 60
2 x 2 x 3 = 12 3 x 7 = 21 2 x 2 x 3 x 7 = 84, the LCM
the prime factorization of 12 in exponents is 2 to the second power times 3
2 x 2 = 4 2 x 3 = 6 2 x 2 x 3 = 12, the LCM
Since 36 is a multiple of 12, it is automatically the LCM, but if you insist... 2 x 2 x 3 = 12 2 x 2 x 3 x 3 = 36 2 x 2 x 3 x 3 = 36, the LCM
22 x 3 = 12
To find the LCM of 12, 30, and 150, we need to decompose the numbers into their prime factors. The prime factorization of 12 is 2^2 * 3, the prime factorization of 30 is 2 * 3 * 5, and the prime factorization of 150 is 2 * 3 * 5^2. Now, we need to choose the common and uncommon prime factors with the highest exponent. The common prime factors are 2 and 3, and the uncommon prime factors are 5 and 2^2. Therefore, the LCM of 12, 30, and 150 is 2^2 * 3 * 5^2 = 300. [1]
5 2 x 2 x 3 = 12 2 x 2 x 3 x 5 = 60, the LCM