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The lowest common denominator of 4, 10 and 6 is 60.

Here is how to solve it:

1. Take the prime factorization, or the prime numbers multiplied to equal each number.

2 x 2 = 4

2 x 5 = 10

2 x 3 = 6

2. Count the number of times each prime factor appears in each case.

Two 2s.

One 2, One 5

One 2, One 3

3. Finally, multiply by the highest number of each unique prime factor.

2 X 2 X 5 X 3 = 60

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16y ago

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