Look at the last digit. If a number's last digit is even, the number is even. If the last digit is odd, the number is odd.
Look at the last digit. If the last digit is even, the entire number is even. If the last digit is odd, the entire number is odd.
Look at the last digit. If the last digit is even, the number is even. If the last digit is odd, the number is odd.
Look at the last digit. If the last digit of a number is even, the whole number is even. If the last digit is odd, the number is odd.
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.
the last even number before 900,000 is 899,998
Any number that has a 2, 4, 6, 8, or 0 in the last place (before the decimal point) is an even number. So, yes.
Look at the last digit. If a number's last digit is even, the number is even. If the last digit is odd, the number is odd.
Look at the last digit. If the last digit is even, the entire number is even. If the last digit is odd, the entire number is odd.
Even b/c if the last number is even then even and if the last number is odd then the number is odd so 986 _6_ is even
Look at the last digit. If the last digit is even, the number is even. If the last digit is odd, the number is odd.
If the last digit is an even number, the whole number is an even number.
Look at the last digit. If the last digit of a number is even, the whole number is even. If the last digit is odd, the number is odd.
If the last number is odd or even then the whole number is odd or even, in this case the last number is 3 which is an odd number, therefore the whole number is odd.
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.
look at the last number like 190,908 so eight is the even number because it's the last number
783 is not an even number as it's last number is 3