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What is the probability of obtaining exactly four tails in five flips of a coin if at least three are tails?
We need to determine the separate event. Let A = obtaining four tails in five flips of coin Let B = obtaining at least three tails in five flips of coin Apply Binomial Theorem for this problem, and we have: P(A | B) = P(A ∩ B) / P(B) P(A | B) means the probability of "given event B, or if event B occurs, then event A occurs." P(A ∩ B) means the probability in which both event B and event A occur at a same time. P(B) means the probability of event B occurs. Work out each term... P(B) = (5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0 It's obvious that P(A ∩ B) = (5 choose 4)(½)4(½) since A ∩ B represents events A and B occurring at the same time, so there must be four tails occurring in five flips of coin. Hence, you should get: P(A | B) = P(A ∩ B) / P(B) = ((5 choose 4)(½)4(½))/((5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0)
What does p stand for on a nickel?
The "P" mintmark shows that the coin was produced by the US Mint at Philadelphia.
When you toss a coin 5 times probability of getting exactly 4 heads?
Because there are only 2 outcomes for the flip of a coin, for 5 flips you just need to take (1/2)5, which equals 1/32. This implies there are 32 different outcomes for the case of tossing a coin 5 times. From these 32 outcomes 5 have exactly 4 heads: THHHH, HTHHH, HHTHH, HHHTH, and HHHHT. So the probability of getting exactly 4 heads when you toss a coin 5 times is: P(4H,!T) = 5/32 = 0.15625 ≈ 15.6%
What is the P(HTTH) on four consecutive flips of a coin?
Oh, what a happy little question! Let's break it down. The probability of getting heads on a single flip is 1/2, and the probability of getting tails is also 1/2. So, the probability of getting HTTH in that specific order on four flips would be (1/2) * (1/2) * (1/2) * (1/2) = 1/16. Just remember, there are no mistakes, just happy little accidents in probability!
A number that has exactly three factors?
A square of any prime number, p has exactly three factors. They are 1, p and p^2.
What is the probability of getting all heads or all tails if you flip a coin three times?
The probability of getting all heads if you flip a coin three times is: P(HHH) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8. The probability of getting all tails if you flip a coin three times is: P(TTT) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8. The probability of getting all heads or all tails if you flip a coin three times is: P(HHH or TTT) = P(HHH) + P(TTT) = 2/8 = 1/4.
what is the p on four flips of a coin?
It is 1/16.
What is the P(HTTH) on four consecutive flips of a coin?
Oh, what a happy little question! Let's break it down. The probability of getting heads on a single flip is 1/2, and the probability of getting tails is also 1/2. So, the probability of getting HTTH in that specific order on four flips would be (1/2) * (1/2) * (1/2) * (1/2) = 1/16. Just remember, there are no mistakes, just happy little accidents in probability!
What is the probability of obtaining exactly four tails in five flips of a coin if at least three are tails?
We need to determine the separate event. Let A = obtaining four tails in five flips of coin Let B = obtaining at least three tails in five flips of coin Apply Binomial Theorem for this problem, and we have: P(A | B) = P(A ∩ B) / P(B) P(A | B) means the probability of "given event B, or if event B occurs, then event A occurs." P(A ∩ B) means the probability in which both event B and event A occur at a same time. P(B) means the probability of event B occurs. Work out each term... P(B) = (5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0 It's obvious that P(A ∩ B) = (5 choose 4)(½)4(½) since A ∩ B represents events A and B occurring at the same time, so there must be four tails occurring in five flips of coin. Hence, you should get: P(A | B) = P(A ∩ B) / P(B) = ((5 choose 4)(½)4(½))/((5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0)
What is the probability of getting at least one head on three tosses of a coin?
In the experiment of tossing a fair coin 3 times, the sample space is made of thefollowing 8 equiprobable events: S = {HHH, THH, HTH, HHT, TTH, THT, HTT, TTT}.The events that at least have one head are 7. So the probability of getting at leastone head on three tosses is: P(at least one H) = 7/8 = 0.875 = 87.5%
Can you simulate a biased coin using a perfect coin?
Yes. Conceptually, color the interval [0,p[ as HEADS and the interval [p,1[ as TAILS, where we use [a,b[ to mean "all numbers from a, inclusive, up through b, exclusive". Now, given an interval with two colors, divide it evenly in half. Use the fair coin to randomly pick one half. If the chosen half has only one color, that is the answer. Otherwise, use the new half as the interval, and repeat the process. How many flips F should you expect to take? Well, at least half the time you stop immediately (end in one interval with just one color), and the other half, you need another F flips. So: F = 1 * 1/2 + (1+F) * 1/2. Multiply through by 2 and simplify to get 2 * F = 1 + 1 + F. Solving for F gives you 2 expected flips.
What is the probability of flipping heads three times in a row?
(1/2)^3 = 1/8 In general it is like this (p/n)^t. Where n is the number of equally possible outcomes (2 since you can get heads or tails), p is the number of desired outcomes (1 since you only are concerned with heads), and t is the number of trials (3 in this case). One caveat to this is that it does not factor in initial conditions. Although very slight you have a better chance of getting heads when the coin is flipped from a position where heads is up. You have less chance of getting heads when the coin is flipped from the tails-up position. This effect is decreased the more the coin flips before landing.
Your 1914 quarter has a p?
If you mean a mint mark on the reverse of the coin, it's a D or S but not a P. Please look at the coin again.
What is the decimal of the odds of a coin being flipped three times coming up heads?
Each time you flip a coin, the probability of a given outcome is1/2. This is multiplied by itself every time you repeat the flip. three times: 1/2 * 1/2 * 1/2 = 1/8 decimal: .125The probability of a fair coin landing heads up is: P(H) = 1/2The probability of a fair coin landing heads up three times is: P(HHH) = (1/2)3 = 1/8= 0.125 = 12.5%One eighth or 12.5%
What is the value of a 1988 penny with no p?
No US one cent coin struck in Philadelphia has ever had a "P" Mintmark so the coin is just a penny.
What is the value of a 1893 5.00 gold coin with a p?
The coin can't have a P mintmark. The only possible mintmarks are O, S or CC. Please, look at the coin again and post new question.
What is the difference from 2000 P 2000 D on the gold coin?
The P or D denote where the coin was made. P=Philadelphia Pennsylvania, D=Denver Colorado. If by "gold coin" you're referring to the Sacajawea dollar, it's brass, not gold - just golden colored.
