sqrt(66) = sqrt(2 x 3 x 11) =
sqrt(2) X sqrt(3) X sqrt(11) or
2^(1/2) X 3^(1/2) X 11^(1/2) = 66^(1/2)
Since 2.3. & 11 are all Prime number , their square roots are Irrational. Hence sqrt(66) is also irrational .
66
approximately .66 repeating
Square root 66 = ± 8.124038404636
The square root of 66 is approximately 8.124. Therefore, the two whole numbers that lie between the square root of 66 are 8 and 9.
1 over 2 times radical 6
66
√264 = √(4 x 66) = 2 √66
approximately .66 repeating
Square root 66 = ± 8.124038404636
The square root of 66 is approximately 8.124. Therefore, the two whole numbers that lie between the square root of 66 are 8 and 9.
12.1240384046
Because the square root of 66 is an irrational number
± 8.1240388.124038404635961
two consecutive integers of the square root of 66 found between
1 over 2 times radical 6
No. Easiest way to check is to simply do the square root of 66 on your calculator. even typing it into google should give you the answer. Square root of 66 = 8.12 or so.
It cannot be simplified.