answersLogoWhite

0

f(x)=x2-x3

f(2) = 4-8 = -4

f'(x) =2x-3x2

f'(2) = 4-12=-8

f''(x) = 2 -6x

f''(2)= -10

f'''(x)= -6

f(n)(x) = 0 for all n > 3.

f(x) = f(2) + (x-2) f'(2) / 1! + (x-2)2 f''(2) /2! + (x-2)3 f'''(2)/3! + . . .

f(x) = -4 -8(x-2) -10(x-2)22/2-6(x-2)3/6 + 0 + 0 + ...

f(x) = -4 -8(x-2) -5(x-2)2 - (x-2)3

User Avatar

Wiki User

14y ago

What else can I help you with?