n1 has 1
n2 has 4
If you add all the digits up, and the total equals a number that 3 can go in, then it's a factor of 3.
The mean, median and mode of one number MUST ALL BE that number.
To find what number equals 98 in 3's timetable, you can divide 98 by 3. Performing the calculation, 98 ÷ 3 equals approximately 32.67, which means there is no whole number that, when multiplied by 3, equals 98. Thus, 98 is not a number in the 3's timetable.
Well 63 divided by 3 equals 21. So 3 times 21 equals 63. 21 is that number.
3 x 3 = 9
There are a total of three p orbitals for an atom with principal quantum number n = 2: px, py, and pz. These orbitals are oriented along the x, y, and z axes.
5 sub-orbitals with (max.) two electrons in each, so 10 in total. This is also true for 4d and 5d orbitalsSymbols:dz2 , dxz ,dyz ,dxy ,dx2-y2
In the third principal level (n=3), there are a total of 3 sublevels: s, p, and d. This means there are 3 orbitals in the third principal level of the atom: one s orbital, three p orbitals, and five d orbitals, making a total of 9 orbitals.
9
In the third energy level, the 3s and 3p sublevels contain a total of 4 orbitals. The 3s sublevel has 1 orbital, while the 3p sublevel has 3 orbitals. The 3d sublevel, which is also part of the third energy level, contains 5 orbitals. Therefore, the total number of orbitals in the 3s, 3p, and 3d sublevels combined is 1 + 3 + 5 = 9 orbitals.
The magnetic quantum number ( m ) for f orbitals can take on integer values ranging from (-l) to (+l), where ( l ) is the azimuthal quantum number associated with f orbitals. For f orbitals, ( l = 3 ), so the possible values of ( m ) are (-3, -2, -1, 0, +1, +2, +3). This results in a total of seven possible values for ( m ).
The shell that contains a total of 9 orbitals is the third shell. This shell consists of one 3s orbital, three 3p orbitals, and five 3d orbitals, which adds up to 9 orbitals in total.
In the third energy level (n=3), there are three sublevels: 3s, 3p, and 3d. The 3s sublevel has 1 orbital, the 3p sublevel has 3 orbitals, and the 3d sublevel has 5 orbitals. Therefore, the total number of orbitals within the 3s, 3p, and 3d sublevels is 1 + 3 + 5 = 9 orbitals.
If the question is an attempt to ask "How many orbitals are there with principal quantum number n = 2", then 4 orbitals which can hold a total of 8 electrons.
principal energy level (n)= 3 Number of orbitals per level(n2)= 9 it equals 9 because it is n2 (32=9) n=1. 1 orbital n=2. 4 orbitals n=3. 9 orbitals n=4. 16 orbitals n=5. 25 orbitals n=6. 36 orbitalsn=7. 49 orbitals
The number of possible different orbital shapes for the third energy level is 3. For n equals 4 the number of possible orbital shape is 4.
3