4x+2y = 20 2y = -4x+20 y = -2x+10
y = -2x+10
For 4x + 2y = 6The X intercept is 1.5The Y intercept is 3
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
4x+2y = 20 2y = -4x+20 y = -2x+10
y = -2x+10
For 4x + 2y = 6The X intercept is 1.5The Y intercept is 3
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
x + 2y = 10At the x-intercept, y=0:x = 10At the y-intercept, x=0 ==> 2y = 10y = 5
-6
-4 + 2y = 242y + 4 = 242y + 4 - 4 = 24 - 42y + 4 - 4 = 24 - 42y = 24 - 42y = 202y/2 = 20/22y/2 = 20/2y = 20/2y = 10Therefore the y-intercept is at (0,10) or has a value of 10
If: -3x+2y = 12 Then: y = 1.5x+6 in slope-intercept form
y-intercept: 2 x-intercept: 4
(0,6)