If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.
zero - it is constat velocity. so acceleration is zero50 m/s2 Another : The acceleration is ZERO. Acceleration is defined as the change in velocity per unit time. If the ball is traveling a constant velocity over a two minute period, the acceleration would be zero since there is no change in velocity.
Time = Distance/Velocity = 2000/55 = 36.3636.. hours = 36 hours 21.8181.. minutes
That's going to depend on where the bus leaves from, or ... what is equivalent ... what direction it has to head in order to get to Alpharetta. You can't talk about a velocity without a direction.
That's an impossible Q. Try me on something easier
If you traveled 25 miles in 2 minutes, your average speed was 25 miles per 2 minutes or 750 miles per hour. If your rate of deceleration was constant, your initial speed was two times 750 miles per hour or 1500 mph. I do not have enough information to determine your initial velocity because I don't know what direction you were going, and velocity is speed with direction.
If the ball is traveling at a constant velocity of 50 m/s, then its acceleration is 0 m/s^2. Acceleration is the rate of change of velocity, so if the velocity is constant, there is no change in velocity, and therefore no acceleration.
zero - it is constat velocity. so acceleration is zero50 m/s2 Another : The acceleration is ZERO. Acceleration is defined as the change in velocity per unit time. If the ball is traveling a constant velocity over a two minute period, the acceleration would be zero since there is no change in velocity.
Oh, dude, acceleration is the rate of change of velocity, not the actual velocity itself. Since the object is traveling at a constant velocity, its acceleration is zero. So, like, it's not speeding up or slowing down, just cruising along at a cool 12 miles per hour west for those 15 minutes.
The acceleration of the body was zero during this interval because its velocity was constant. Acceleration is the rate of change of velocity, so if the velocity does not change, the acceleration is zero.
1). If neither speed nor direction are changing, then acceleration is zero.2). "minutes" is not a unit of velocity, but we get the idea
As long as the 30 minute are spent driving in a straight line, the acceleration is zero.
Constant speed (in a straight line) means there is no acceleration.Constant speed (in a straight line) means there is no acceleration.Constant speed (in a straight line) means there is no acceleration.Constant speed (in a straight line) means there is no acceleration.
The average velocity is trying to find how fast the car is going at an average rate. However, constant velocity means that the car is going at an unchanged velocity. Say a car is going at 75 m/s and then changes to 50 m/s and then changes to 25 m/s in 30 minutes. The car is going at different velocities at different times. To find the average, you simply just add the 3 together, then divide by 3 giving you, 50 m/s In the 30 minutes, it's average velocity was 50 m/s However, for a car going at a constant velocity, it means that the velocity never changes. Say a car is going at a constant velocity for 30 minutes at 50 m/s. In those 30 minutes, the car will never change it's velocity and remain at 50 m/s. Constant means that it doesn't change.
s= .5gt^2 give t = sqrt(400Mm/9.8) =6388.76 secs or 106.479 minutes or 1.7746 hours..
It depends how fast you are traveling. if there is no acceleration, use time= distance/speed. for linear acceleration google SUVAT equations.
Average acceleration is a change in velocity over a period of time:a = Δv/Δt"a car is traveling 100 km/hr and comes to a stop..." implies that its original speed, let's call it v_0, was given by:v_0 = 100 km / 1 hr= 100,000 m / 3600 s= 27.77... m/sand its final velocity, called v_f, isv_f = 0.so Δv, the CHANGE in velocity, was v_f - v_0, orΔv = 0 - 27.77... = -27.77... m/sand Δt, the change in time, was "3 min[utes]."Δt = 3 minutes= 180 ssoa = Δv/Δt= (-27.77... m/s) / 180s= -0.1543 m/s/sNote that I arbitrarily chose to assign the car's initial velocity a positive sign.
To find the rate of deceleration, we first need to convert the time from minutes to seconds. 3 minutes = 180 seconds. Next, we use the equation of motion: final velocity^2 = initial velocity^2 + 2 * acceleration * distance. Since the boat comes to a stop, the final velocity is 0 m/s. Substituting the values and solving for acceleration, we get a deceleration rate of 0.139 m/s^2.