If you want to have that in meters per second square, convert the speed to meters per second (divide by 3.6 in this case). Then, divide the speed by the time.
10000 m/s2.
10 km per hour per second.
well we know that we have two speeds and a time. So, initial speed = 80 final speed = 60 change in time = 6 Now acceleration in this case will be measured in kilometers per hour per second (i.e. every x seconds, y kilometers per hour are gained in speed) So we simply apply the formula Acceleration = (final speed - initial speed)/ change in time = (80 - 60)/6 = 20/6 = 3.6666667 km/h/s
You can't figure "acceleration" from this information. Maybe you meant "Deceleration"? Ask again.
The answer is very simple. The words "constant velocity" are the definition of zero acceleration.
10000 m/s2.
10 km per hour per second.
smart
"Constant rate" implies there is no acceleration - acceleration is zero.
well we know that we have two speeds and a time. So, initial speed = 80 final speed = 60 change in time = 6 Now acceleration in this case will be measured in kilometers per hour per second (i.e. every x seconds, y kilometers per hour are gained in speed) So we simply apply the formula Acceleration = (final speed - initial speed)/ change in time = (80 - 60)/6 = 20/6 = 3.6666667 km/h/s
The acceleration of the car is 0.5 m/s^2. This is calculated by dividing the change in velocity (40 m/s) by the time taken (80 seconds).
It is 0.1 metre per second-squared.
You can't figure "acceleration" from this information. Maybe you meant "Deceleration"? Ask again.
The answer is very simple. The words "constant velocity" are the definition of zero acceleration.
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
It is 0.1 metre per second-squared.