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What is the average acceleration of a car goes form 0 to 60 mph in 2.1 seconds?
Average acceleration = (change in speed) / (time for the change) = (60 - 0) / (2.1) = 28.571 miles per hour per second, or 41.905 feet per second2 Using: (1 mile / hour - second) x (5,280- ft / mile) / (3,600 second / hour) = 1.4666 ft/sec2
How do you write three one hundredths of a second in decimal form?
0.03 seconds.
How do you write fifteen hundredth of a second write the decimal in standard and expanded forms?
Standard form: 1.5*10-1 seconds, expanded form: (0.1 + 0.05) seconds.
How do you write 4 tenths of a second?
Four tenths of a second can be written as 0.4 seconds. In fraction form, it is expressed as ( \frac{4}{10} ), which can be simplified to ( \frac{2}{5} ) seconds. Additionally, it can be represented in milliseconds as 400 milliseconds (ms).
How long does it take To Travel 844 Miles At 65 Miles Per Hour?
For a rough estimate, travelling for 13 hours would be 845 miles (13*65=845)A fairly exact solution:844 miles/65mph=12.98 hours.0.98 hours = 58.8 minutes0.8 minutes = 48 seconds12 hours 58 minutes 48 secondsFor an exact solution:Every hour has 60 minutes or 3600 seconds. 65 miles per hour is a mile every 3600/65 seconds.844 miles * 3600/65 seconds = 3038400/653038400/65 simplified is 607680/13.607680/13 is exactly the number of seconds it would take. That is 46744.615384... seconds. The 615384 repeats endlessly.46744.615384... seconds is equal to 12 hours 59 minutes 4 seconds .615384... seconds. 607680/13 is the answer in fraction form.
What is the average acceleration of a car goes form 0 to 60 mph in 2.1 seconds?
Average acceleration = (change in speed) / (time for the change) = (60 - 0) / (2.1) = 28.571 miles per hour per second, or 41.905 feet per second2 Using: (1 mile / hour - second) x (5,280- ft / mile) / (3,600 second / hour) = 1.4666 ft/sec2
How do you write in number form a half a second?
0.5 seconds
How do you write out 1 billionth of a second in standard form?
1 billionth of a second in standard form is: 1.0 × 10-9 seconds.
How do you write three one hundredths of a second in decimal form?
0.03 seconds.
How do you write fifteen of a second in decimal in standard and expanded form?
It is 1.5*10-1 seconds, which is 10 + 5 seconds.
How do you write out one-billionth of a second in standard form?
1.0 × 10-9 seconds.
How do you write fifteen hundredth of a second write the decimal in standard and expanded forms?
Standard form: 1.5*10-1 seconds, expanded form: (0.1 + 0.05) seconds.
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
SI unit for force of gravity?
Gravity is a form of acceleration and so is measured in metres per second^2.
The SI unit for expressing gravity is what?
Gravity is a form of acceleration and so is measured in metres per second^2.
Formula for accleration?
There are several formulae that involve acceleration. The most basic one is the definition of acceleration, which is: a = (difference in velocity) / time This assumes constant acceleration. For non-constant acceleration, the more general formula is: a = dv / dt where "dv" is the difference in velocity, and "dt" is the time interval, with the additional assumption that it is a very small time interval. For more details, read an introductory calculus book, to understand the concept of "derivative".
What states that acceleration of an object is in the same direction as the net force on the object?
This follows from Newton's Second Law, if expressed in vector form.
