12m/s2
1300m/s-1240m/s = 60m/s =12m/s
5s 5s s
12m/s/s=12m/s2
a = m/s/s a = 560/1/7 a = 80m/s/s
vt = velocity at time tv0 = initial velocitya = accelerationt = timevt = v0 + a * tvt = 1000 + 4 * 100vt = 1400 m/s
742.5742 meters/sec 9000meters/12.12sec x .00062137miles/1meter x 60sec/1min x 60min/1hr = 1660.9miles/hr Sorry, miles per hour is probably the units you wanted. Here's meters/sec AND miles/hr.
Reduced atmospheric drag at higher altitudes, Acceleration due to the thrust of the rocket's engine(s).
There are a couple of pieces of information you'll need first. Here they are:-- 1 mile = 1,609.344 meters-- 1 hour = 3,600 secondsNow, take your miles-per-hour number, and multiply it by ' 1 ' a couple of times.(Remember that a fraction with the same thing on the top and bottom is equal to ' 1 '.)(X miles/hour2 ) x (1,609.344 meters/mile) x (1 hour/3,600 seconds)2 = 0.00012418 X meters/sec2Massage this result for a bit, and you discover that if you have enough fuel aboardyour rocket ship to keep pumping along at the acceleration of "1 G", then you'refeeling pretty comfortable inside, even though at the end of the hour, you've justhit 78,974 mph and you're still gaining.Why, at that rate of acceleration, 10% of the speed of light is only 35.4 days away !
what is the speed of a rocket that travels 9000 meters in 12.12 seconds
A rocket that travels 9000 meters in 12.12 seconds moves at 742.5742 meters/second which is approx 1660 mph
8000m/12sec.
F = M A whence A = F/M .Acceleration is directly proportional to the force applied to the rocket, and inverselyproportional to the rocket's mass. If you need to increase the acceleration, you havetwo choices . . . either reduce the rocket's mass, or increase the force applied to it.That means you must either toss something overboard, or else burn fuel faster.There's no other way.
F = M A whence A = F/M .Acceleration is directly proportional to the force applied to the rocket, and inverselyproportional to the rocket's mass. If you need to increase the acceleration, you havetwo choices . . . either reduce the rocket's mass, or increase the force applied to it.That means you must either toss something overboard, or else burn fuel faster.There's no other way.
-- The rocket's initial speed was zero.-- In 21 seconds, it traveled 4,700 meters.-- Its average speed was 4,700/21 meters per second.-- Since that was its average speed, and its initial speed was zero, its final speedmust have been double that = 9,400/21 meters per second.-- Acceleration = (change in speed) / (time for the change)= (9,400/21) divided by (21) = 21.315 meters per second2 .==================================Or you could just use the formula [ D = 1/2 A T2 ] .4,700 = 1/2 A (21)29,400 = A (21)2A = 9,400 / 212 = 21.315 meters per second2Notice that we don't care wherther ther mass of the rocket is 1 milligram,1,000 kg, or a bazillion metric tons. Makes no difference.
16200 Km/Hour
The period of the pendulum will be less than 1 second as soon as the rocket begins to accelerate off of the pad, because the so-called 'G-force' inside it increases during that time. After a while, when it has lifted some distance from the surface and the acceleration due to gravity is less, we no longer have enough information to describe the pendular behavior. Whenever the sum of the remaining gravitational acceleration plus the rocket's acceleration exceeds 9.8 m/s2 , its period is less than 1 sec. If the sum is less than normal surface gravity, the period of the pendulum is more than 1 sec.
The acceleration of a rocket depends on the thrust produced by the engine and the mass of the rocket. A higher thrust will result in greater acceleration, while a higher mass will decrease acceleration. Air resistance can also affect acceleration, with lower air resistance allowing for greater acceleration.
9,000/320 = 28.125 seconds
To find the velocity attained by the rocket, we can use the equation: velocity = initial velocity + (acceleration x time) First, calculate the acceleration using Newton's second law: acceleration = force / mass = 5 x 10^5 N / 2 x 10^4 kg = 25 m/s^2 Next, plug the acceleration and time (20 seconds) into the formula to find the final velocity: velocity = 0 + (25 m/s^2 x 20 s) = 500 m/s.
A heavier rocket will have a lower acceleration compared to a lighter rocket, assuming the same amount of force is applied. This is because the heavier rocket will require more force to overcome its inertia and accelerate.