Q: What is the angle of each exterior angle of a regular polygon with 15 sides?

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With a regular polygon: 360/exterior angle = number of sides

Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)

360/exterior angle = number of sides of a regular polygon

A regular polygon will have 360 sides with exterior angles of 181 degrees.

360/number of sides = exterior angle

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With a regular polygon: 360/exterior angle = number of sides

Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)

by the number of sides, 'n' of that particular polygon. by the exterior angle. Therefore, the number of sides of the polygon is 24 sides.

360/number of sides = exterior angle

360/exterior angle = number of sides of a regular polygon

A regular polygon that has an exterior angle of 60 degrees = 360/60 = 6 sides and it is an hexagon

A regular polygon with an exterior angle of40O is a nonagon, and has 9 sides.

A regular polygon will have 360 sides with exterior angles of 181 degrees.

5 sides, a regular pentagon.

By dividing the given exterior angle into 360 degrees tells you how many sides the polygon has.

360/number of sides = exterior angle

Each exterior angle is 15 degrees