Since the span between 12 and 2 is 2 hours, and there are 12 hours on a round analogue clock face, it stands to reason that you are essentially dividing a circle into 6 equal pieces by virtue of the 12 hours divided by the two hour span. And if there are 360 degrees in a circle, then one sixth of 360 degrees would leave you with 60 degrees. Therefore the angle between the hands at 12 and 2 O'clock is 60 degrees.
At 12 o'clock, the minute hand points at 12, and the hour hand also points at 12. Since both hands are aligned, the angle between them is 0 degrees. Therefore, the angle between the hands of a clock at o'clock is always 0 degrees.
Right Angle or 900
On a typical 12-hour clock face, the angle between the hands at 1:00 is1/12th of the whole circle.That's (360/12) = 30 degrees.
so you have moved 2/12 around a clock. there are 3600 around the full clock, so: 360/12 is 30, 30x2 is 600.
The number of memory between 12 and 1 is 5. There are 60 lines in a clock: 5/60. Since the whole angle of the clock is 360, you multiply 360 and 5/60 together and get the answer of 30 degrees.
At 12 o'clock, the minute hand points at 12, and the hour hand also points at 12. Since both hands are aligned, the angle between them is 0 degrees. Therefore, the angle between the hands of a clock at o'clock is always 0 degrees.
Right Angle or 900
On a typical 12-hour clock face, the angle between the hands at 1:00 is1/12th of the whole circle.That's (360/12) = 30 degrees.
so you have moved 2/12 around a clock. there are 3600 around the full clock, so: 360/12 is 30, 30x2 is 600.
The answer depends on the angle between WHAT and WHAT!
The number of memory between 12 and 1 is 5. There are 60 lines in a clock: 5/60. Since the whole angle of the clock is 360, you multiply 360 and 5/60 together and get the answer of 30 degrees.
The hands of a clock at 5 to 12
15 + 5 x 30 ie 165o
44. 22 in each 12 hour cyccle.
Imagine two clock hands two minutes apart.
11
At 3:00 (1500 hours) on a clock, the hour hand is pointing directly at the 3 and the minute hand is pointing at the 12. To find the angle between the hands, we can use the formula: |(30*H) - ((11/2)M)|, where H is the hour and M is the minute. Plugging in the values, we get |(303) - ((11/2)*0)| = |90 - 0| = 90 degrees. Therefore, the angle between the hands of the clock at 1500 hours is 90 degrees.