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How do you work out the interior angles of a 25 sided polygon?
To find the interior angles of a 25-sided polygon (icosikaipentagon), you can use the formula for the sum of interior angles, which is ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a 25-sided polygon, this calculation would be ( (25 - 2) \times 180^\circ = 23 \times 180^\circ = 4140^\circ ). To find the measure of each interior angle in a regular 25-sided polygon, divide the total sum by the number of sides: ( \frac{4140^\circ}{25} = 165.6^\circ ).
What is the sum of the interior angle measures of a 15 sided polygon?
Remember Exterior angle = 360 / No. of sides. Hence Exterior Angle = 360//25 = 24 degrees, It follows that the intertiot angle is 180 - 24 =156 degrees. There are 15 interior angles Hence 15 x 156 = 2340 degrees is the sum of the interior angles of a 'Pentadecagon'.
Find the measure of an interior angle of a regular polygon with 25 sides?
Method 1: Interior angles of a regular n-sided polygon total (2n - 4) right angles or 180n - 360 degrees. Each angle is therefore ((180 x 25) - 360)/25 ie 165.6 degrees. Method 2: EXterior angles of regular n-sided polygon = 360/n degrees, in this case 360/25 ie 14.4 degrees. Interior angle = 180 - exterior ie 180 - 14.4 = 165.6 degrees.
What is the sum of the interior angles of a polygon with 25 sides?
The formula for the sum of the interior angles of a polygon is: 180 * (n - 2) where n is the number of sides of the polygon. So the sum of the angles of a polygon with 25 sides is 180 * 23 = 4,140.
Why the size of the angle at the centre of a regular polygon cannot be 25 degrees?
Because 25 does not divide 360.
