Let the number be x and so if 3x+5 = 41 then x = 12
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The sum of the squares of two consecutive positive numbers is 41.What is the smaller number?Improved Answer:-It is 4 because 42+52 = 41
4+5 = 9 42+52 = 41
The additive inverse of 41 is -41. An additive inverse is the number that will make the sum equal zero.
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