When working with mixed numbers it is (usually) easier to work with improper fractions and convert any resulting improper fraction back to a mixed number.
2/3 × 3 3/5 = 2/3 × (3×5+3)/5
= 2/3 × 18/5
= (2×18)/(3×5)
= 36/15
= 12/5
= (2×5+2)/5
= 2 2/5
2/5 divided by 2/3 = 3/5
2 over 3 divided by 3 over 5 [2/3] / [3/5] is the same as 2 times 5 over 3 times 3 [2*5] / [3*3] 10/9 1 1/9 1.111... The answer is 1 and 1/9
3/4 × 2/5 = (3×2)/(4×5) = 6/20 = 3/10
6/5 + 4/5 = 10/5 = 2 * * * * * No. 3 and 3 over 5 is 33/5, not (3+3)/5 So, the required sum is 33/5 + 22/5 = 3 + 2 + 3/5 + 2/5 = 5 + 5/5 = 6
2 over 5. 1/3 = 33% 2/5 = 40%
3/2 ÷ 3/5 = 3/2 x 5/3 = 5/2 = 21/2
2/5 divided by 2/3 = 3/5
1 2/3=5/3 (2/3)/(5/3)=(2/3)*(3/5)=2/5
(3/5) / (3/2) = (3/5) x (2/3) = 6/15 = 2/5
2 over 3 divided by 3 over 5 [2/3] / [3/5] is the same as 2 times 5 over 3 times 3 [2*5] / [3*3] 10/9 1 1/9 1.111... The answer is 1 and 1/9
3 over 5
3/4 × 2/5 = (3×2)/(4×5) = 6/20 = 3/10
1 5/2 - 3/2 = (5-3)/2 = 2/2 = 1
6/5 + 4/5 = 10/5 = 2 * * * * * No. 3 and 3 over 5 is 33/5, not (3+3)/5 So, the required sum is 33/5 + 22/5 = 3 + 2 + 3/5 + 2/5 = 5 + 5/5 = 6
2 over 5. 1/3 = 33% 2/5 = 40%
2 over 5
3/5 / 2/3 =9/10