3 = X + 3 - 5X
combine variable terms
3 = - 4X + 3
subtract 3 from each side
0 = - 4X
divide each side integer by - 4
0/- 4 = (- 4/- 4)X
0 = X
========check in original equation
3 = (0) + 3 - 5(0)
3 = 3
======checks
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x=0
5x plus 3 does equal 3 plus 5x; commutative law.
X=-3
3x + 7 = 5x + 13 3x - 5x = 13 - 7 -2x = 6 -x = 3 x = -3
5x+3 = 3x+11 5x-3x = 11-3 2x = 8 x = 4