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x² - 6x -8 = -56

<=> x² -6x + 48 = 0

We now calculate the discriminant (which equals b²-4ac for an equation of the form ax² + bx + c-:

D = b²-4ac = (-6)² - 4*1*48 = 36 - 192 = -156

I don't know what kind of course in calculus you are taking, but if you only want the real answers to this equation, you can stop here because the discriminant is negative, meaning there are no real solutions. However, there are complex solutions to this equation

The complex roots of D are sqrt(156)*i=12,5*i and -sqrt(156)*i=-12,5*i

There are two solutions to a quadratic equation, namely:

x1 = (-b + sqrt(D))/(2*a)

and x2 = (-b - sqrt(D))/(2*a)

so the two solutions we find for this equation are:

x1 = (-b + sqrt(D))/(2*a) = (6+12,5i)/2 = 3+6,25i

and x2 = (-b - sqrt(D))/(2*a) = (6-12,5i)/2 = 3-6,25i

x1 and x2 are complex solutions to this quadratic equation.

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Q: What is the answer for x x -6x-8 equals -56?
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