4x10=40, 4x2=8, 40+8=48 and theres your answer.
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β 13y ago346
23 + 2 19 + 3 + 3 17 + 5 + 3 17 and 4 twos 17, 2 threes and 2 twos 13 + 7 + 5 13 and 6 twos 13 and 4 threes 11 and 2 sevens 11 and 7 twos and a bunch more up to 10 twos and 5 11 twos and 3
3 ones
4, one per suit.
There are 4 two's in deck of 52 cards.
7 twos
yes
12
346
4
23 + 2 19 + 3 + 3 17 + 5 + 3 17 and 4 twos 17, 2 threes and 2 twos 13 + 7 + 5 13 and 6 twos 13 and 4 threes 11 and 2 sevens 11 and 7 twos and a bunch more up to 10 twos and 5 11 twos and 3
4 tires on a car
Because they are both multiples of two, so when they're added, the sum must be another multiple of two. (One group of twos plus another group of twos must be a new group of twos, just like one group of cows plus another group of cows must be a new group of cows.)
4!-(4/4+4)=19
√(2+2)+2
There are nine twos in eighteen.
64 twos go into 128.This is not hard to do. If you look at the first two figures - 12 - and ask how many twos in 12 the answer is 6 (6x2=12). Then look at the last figure - 8 - and ask how many twos in eight, the answer is 4 (2x4=8). The answer is 64.