j=-3 and k=2
Take 3k from both sides to get k-3 equals 4, so k is 7
k = -3; factors are (9x + 3)(x - 1)
k = 0.1
3k + 3 = 8 3k = 8 -3 3k = 5 k = 5/3
j=-3 and k=2
Take 3k from both sides to get k-3 equals 4, so k is 7
k = -3; factors are (9x + 3)(x - 1)
3k-1=k+2 2k=3 k=3/2=1.5
y = 3x + 2x^2 + k where k is any number
Yes, they are exactly the same, both of them increment k in 1.
k equals 5.6
k = 0.1
3k + 3 = 8 3k = 8 -3 3k = 5 k = 5/3
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
50
It simplifies to 7k = 49 which gives k = 7.