14 + 6p = 6 + 7p 8 = p
8p+5 = 11+7p= 8p-7p = 11-5p = 6
7p + 2 = 5p + 8 7p - 5p = 8 - 2 2p = 6 p = 3
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
p=-3
14 + 6p = 6 + 7p 8 = p
8p+5 = 11+7p= 8p-7p = 11-5p = 6
7p + 2 = 5p + 8 7p - 5p = 8 - 2 2p = 6 p = 3
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
p=-3
15 + 3 = 7p - 4p ie 18 = 3p so p = 6
7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)
The electron configuration of chlorine (Cl) is 1s2 2s2 2p6 3s2 3p5. It has 17 electrons distributed among its energy levels and orbitals.
??7P ??Y? 4??? +F?? F4?6 K???
132
6x12=72+654=726+555= 1281
6. Electronic configuration, 1s2 2s2 2p6, 3s2, 3p5