p = -1
p + (-2) = 1 so p - 2 = 1 Add two to both sides: p = 3
x = (P - 2W) / 2
4p+9-7p+2 -3p+11 p = 11/3
yes
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
no it equals one :P
p+2 = 2-3p p+3p = 2-2 4p = 0 p = 0
The letter "p" in the symbol 4p3 indicates the variable representing a number that is to be raised to the power of 3.
p + (-2) = 1 so p - 2 = 1 Add two to both sides: p = 3
9p - 5
x = (P - 2W) / 2
Solving by elimination: p = 3 and q = -2
The electron configuration of arsenic is [Ar] 3d10 4s2 4p3. This means that arsenic has 2 electrons in its outermost shell (4s2 4p3) and belongs to the p-block of the periodic table.
The value of p is 1.4
p + 32
4p+9-7p+2 -3p+11 p = 11/3
p=1125