If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
7
(5,3)
10*6+8*7 = 116
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
2x = -7 - 8y
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
7
(5,3)
10*6+8*7 = 116
7 + 8y - 3y + 2 =7 + 2 + 8y - 3y = 9 + 8y - 3y = 9 + 5y
7
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
yes
3
(5 - 11y - 12) + 8y = 5 - 11y - 12 + 8y = ( - 7 - 3y )
Let the numbers be x and y:- If: x+3y = -4 and 3x+y = 44 Then: 3x+9y = -12 and 3x+y = 44 Subtracting 3x+9y = -12 from 3x+y = 44: -8y = 56 => y = -7 By substitution: x = 17 and y = -7 Check: 17+3(-7) = -4 Check: 3(17) -7 = 44 Therefore the two numbers are: 17 and -7