6x3 - x2 + 17 = 2x2 + 47 6x3 - x2 - 2x2 = 47 - 17 x2(6x - 1 - 2) = 30 this is the simplest factorisation.
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
2x2 + x2 = 3x2
The solution to the problem 2x2 is 4 (the result of multiplication).
2x2 = x2 - 2 Subtract x2 from both sides: x2 = -2 Take square roots: x = + or - i*sqrt(2) where i is the imaginary sqrt of -1.
x2 + x2 = 2x2
x2 + x2 = 2x2
6x3 - x2 + 17 = 2x2 + 47 6x3 - x2 - 2x2 = 47 - 17 x2(6x - 1 - 2) = 30 this is the simplest factorisation.
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
To solve the expression 2x2 times x2, we first simplify the multiplication of the coefficients: 2 x 2 = 4. Next, we multiply the variables with the same base (x) by adding their exponents: x2 x x2 = x(2+2) = x4. Therefore, the final answer is 4x4.
2x2 + x2 = 3x2
2x2=4 X -2=-8
The solution to the problem 2x2 is 4 (the result of multiplication).
2x2 = x2 - 2 Subtract x2 from both sides: x2 = -2 Take square roots: x = + or - i*sqrt(2) where i is the imaginary sqrt of -1.
the difference between 2x2 +4xy-3 and x2-2xy-4 is?
x2 - (2x)2 = x2 - 4x2 = -3x2 x2 - 2x2 = -x2
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2