The answer to this question is -27. This is taught in math class.
h = 5 5x5=25 +2=27-5=22
5h + 6 = 25 Subtract 6 from both sides: 5h = 19 Divide both sides by 5: h = 3.8 h = 3.8
It is the same as 5h+20 = 5(h+4)
It is 5*12 - 2 = 58.
To calculate ( 5h - 2 ) when ( h = 12 ), substitute 12 for ( h ): [ 5(12) - 2 = 60 - 2 = 58. ] Thus, the result is 58.
h = 5 5x5=25 +2=27-5=22
It is an equation.
5h + 6 = 25 Subtract 6 from both sides: 5h = 19 Divide both sides by 5: h = 3.8 h = 3.8
It is the same as 5h+20 = 5(h+4)
8h - 10h = 3h + 25-2h = 3h + 25-5h = 25-h = 5h = -5
If you mean C = 5h-2 then C = (5*12)-2 => 58
It is 5*12 - 2 = 58.
It is: (5*12)-2 = 58
To calculate ( 5h - 2 ) when ( h = 12 ), substitute 12 for ( h ): [ 5(12) - 2 = 60 - 2 = 58. ] Thus, the result is 58.
No because 35h is greater than 5h. 5 times h can be written as 5h.
5 hours
4fg^-5 / 5h^-3 = 4fh^3/5g^5