If a + b = 6, what is the value of 3a + 3b?
b = -6
12a + 6b + 6c = 6(2a + b + c)
6+7a+6b
n + 6 = 18 n = 12
20+3b = 20 + 3(-6) = 20-18 = 2
If a + b = 6, what is the value of 3a + 3b?
3b + 6 = 12 3b = 6 b = 2
6
b = -6
12a + 6b + 6c = 6(2a + b + c)
3b + 2a = 2 and -2 + a = 8 -2 + a = 8 can be rearranged to show a = 8 + 2 = 10 (Effectively 2 has been added to both sides.) As a = 10, the value for a can now be substituted in the equation 3b + 2a = 2 3b + 2x10 = 2 : 3b + 20 = 2 this can be rearranged to show 3b = 2 - 20 = -18 and dividing both sides by 3 gives b = -6.
6+7a+6b
-6(a-3b-9c)
18
It is: 4b+6
Equality