How do you solve 3b plus 2a equals 2 and -2 plus a equals 8?
3b + 2a = 2 and -2 + a = 8
-2 + a = 8 can be rearranged to show a = 8 + 2 = 10 (Effectively
2 has been added to both sides.)
As a = 10, the value for a can now be substituted in the
equation 3b + 2a = 2
3b + 2x10 = 2 : 3b + 20 = 2 this can be rearranged to show 3b =
2 - 20 = -18
and dividing both sides by 3 gives b = -6.