There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows:
6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11)
Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
0. 6x + 3 = 5x + 141. 6x = 5x + 11 [subtracting 3]2. x = 11 [subtracting 5x]
6x2-5x-21 = (3x-7)(2x+3)
When factored it is: (6x-1)(6x+1)
-116
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
5x + x = 5x Squared (5x^2) x + x equals 2 x's = 2 = squared - very simple & logic. no its not simple and logic 5x^2 is the result of 5x times x. 5x plus x is 6x. Think of the x as 1x not x so 1x + 5x= 6x. That's simple and logic.
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
0. 6x + 3 = 5x + 141. 6x = 5x + 11 [subtracting 3]2. x = 11 [subtracting 5x]
x = 0,1
4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x
x^(2) + 5x^(2) = 6x^(2) Think of it as 2 + 5(2) = 6(2) ( 2 + 10 = 12 = 6(2)) Note : You just add the coefficients(numbers)/. However, be careful and note the difference for multiplication. x^(2) X 5x^(2) = 5x^(4) ( That is 'five 'x' to the fourth power'). In this case x^(2) means x X x and 5x^(2) = 5 X x X x , so on multiplication it becomes 5 X x X x X x X x = 5x^(4)
6x2-5x-21 = (3x-7)(2x+3)
5x2 - 6x = 0Factor the left side:x (5x - 6) = 0The equation is satisfied ifx = 0,or if5x - 6 = 05x = 6x = 6/5
When factored it is: (6x-1)(6x+1)
-116
-5x+1 = 6x -5x-6x = -1 -11x = -1 x = 1/11