Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
It is a straight line equation that needs to be rearranged into slope-intercept form as folows:- 7x+2y = 5 Subtract 7x from both sides: 2y = -7x+5 Divide all terms by 2: y = -3.5x+2.5 which is now in slop-intercept form
the answer to this problem is -2x^2y^2
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
7x is still the slope, no matter what x equals.
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
It is a straight line equation that needs to be rearranged into slope-intercept form as folows:- 7x+2y = 5 Subtract 7x from both sides: 2y = -7x+5 Divide all terms by 2: y = -3.5x+2.5 which is now in slop-intercept form
the answer to this problem is -2x^2y^2
7x-2y=10 -2y=10-7x y=-5+(7/2)x y=(7/2)x-5 (Final answer)
y equals -1/3x plus 4/3
5x - 3y -7x + 2y +3x = (5-7+3)x + (-3+2)y = x - y
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
7x = 5+5x 7x-5x = 5 2x = 5 x = 2.5
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
7x is still the slope, no matter what x equals.
4x+5=7x-8 the ansewr is 3.25