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f(x) = -x2 is a function. The equation is solved with just f(x) on one side, and if you were to graph it, it would pass the vertical line test.
True
Yes. It is a piece-wise function with the limit: lim{x->0}= 0 You graph both parts as two series of dotted lines since there are infinite rational and irrational possibilities
graph G(x)=[x]-1
The result depends on how the function f() is defined. Simply copy the function definition, replacing every "x" (assuming the function is defined in terms of "x") by "x+5".
graph gx is the reflection of graph fx and then transformed 1 unit down
y=x
at first draw the graph of fx, then shift the graph along -ve x-axis 21 unit
The graph of the function f(x) = 4, is the horizontal line to the x=axis, which passes through (0, 4). The domain of f is all real numbers, and the range is 4.
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What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
f(x) = -x2 is a function. The equation is solved with just f(x) on one side, and if you were to graph it, it would pass the vertical line test.
True
Yes. It is a piece-wise function with the limit: lim{x->0}= 0 You graph both parts as two series of dotted lines since there are infinite rational and irrational possibilities
[fx] is a function of x, it usually used in graphs.
False
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.