5-2x3
5-6
-1
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3*(5+x) or 3(5+x)
The multiple of 3 nearest to and below 1000 is 999. 999/3 = 333 The sum of all the multiples is 3 x 333 x 334/2 = 166833 The multiple of 5 nearest to and below 1000 is 995. 995/5 = 199 The sum of all the multiples is 5 x 199 x 200/2 = 99500
10 you plus them all together x
Suppose the samller of the two integers is x, then the other, being consecutive, is x+1. So x*(x+1) = x+(x+1) + 5 or x2 + x = 2x + 6 so that x2 - x - 6 = 0 This is equivalent to x2 - 3x + 2x - 6 = 0 ie x(x - 3) + 2(x - 3) = 0 (x - 3)(x + 2) = 0 So x = -2 or x = 3 x = -2 gives the solution -2 and -1 whose product (+2) is 5 more than their sum (-3) and x = 3 gives the solution 3 and 4 whose product (12) is 5 more than their sum (7).
The integers are -5 and -3: Where the first integer is x (and the second is x+2) x+(x+2) = -8 x+x+2 = -8 2x + 2 = -8 2x = -10 x = -5 and x+2 = -3