3*(5+x) or 3(5+x)
The multiple of 3 nearest to and below 1000 is 999. 999/3 = 333 The sum of all the multiples is 3 x 333 x 334/2 = 166833 The multiple of 5 nearest to and below 1000 is 995. 995/5 = 199 The sum of all the multiples is 5 x 199 x 200/2 = 99500
10 you plus them all together x
Suppose the samller of the two integers is x, then the other, being consecutive, is x+1. So x*(x+1) = x+(x+1) + 5 or x2 + x = 2x + 6 so that x2 - x - 6 = 0 This is equivalent to x2 - 3x + 2x - 6 = 0 ie x(x - 3) + 2(x - 3) = 0 (x - 3)(x + 2) = 0 So x = -2 or x = 3 x = -2 gives the solution -2 and -1 whose product (+2) is 5 more than their sum (-3) and x = 3 gives the solution 3 and 4 whose product (12) is 5 more than their sum (7).
The integers are -5 and -3: Where the first integer is x (and the second is x+2) x+(x+2) = -8 x+x+2 = -8 2x + 2 = -8 2x = -10 x = -5 and x+2 = -3
2(x + 3)= 5? x + 3 = 2½ x = -½
The prime factorization of 36 is 2 x 2 x 3 x 3. The sum of the prime numbers 2 and 3 is 5.
x/3 + 7 = 5 x/3 = -2 x = -6
1 x 2 x 3 x 4 x 5 x 6 = 720 When they are multiplied they produce a product, not a sum. Addition produces a sum.
-5
3*(5+x) or 3(5+x)
The two numbers are -3 and -2. -3 + -2 = -5 -3 x -2 = 6
The multiple of 3 nearest to and below 1000 is 999. 999/3 = 333 The sum of all the multiples is 3 x 333 x 334/2 = 166833 The multiple of 5 nearest to and below 1000 is 995. 995/5 = 199 The sum of all the multiples is 5 x 199 x 200/2 = 99500
10 you plus them all together x
-2
2 x 3 x 3 x 3 = 54 3 x 3 x 5 = 45
30 = 2 x 3 x 510 = 2 + 3 + 5Therefore the numbers are 2, 3 and 5.