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To find the values of x and y that satisfy the system of equations x + y = 4 and y = 2x + 1, you can substitute the expression for y from the second equation into the first equation. This gives you x + (2x + 1) = 4. Simplifying, you get 3x + 1 = 4, which leads to 3x = 3 and x = 1. Substituting x = 1 back into the second equation, you find y = 2(1) + 1, so y = 3. Therefore, the solution to the system of equations is x = 1 and y = 3.
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What is the answer to 2x plus 5 plus x2x-1 plus 2x plus 4?
x equals 4
2x plus 5 equals 3x plus 1?
2x+5=3x+1 -x=-4 x=4
4 plus 2x- -2x plus 1 equals 13 plus 6?
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
2x plus y equals 7 x plus y equals 4?
(3, 1)
3x plus 2y equals 10 2x plus 5y equals 3?
(4, -1)
What is the answer to 2x plus 5 plus x2x-1 plus 2x plus 4?
x equals 4
2x plus 5 equals 3x plus 1?
2x+5=3x+1 -x=-4 x=4
What is the x in x plus 4 equals 2x plus 3?
1
4 plus 2x- -2x plus 1 equals 13 plus 6?
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
2x plus y equals 7 x plus y equals 4?
(3, 1)
3x plus 2y equals 10 2x plus 5y equals 3?
(4, -1)
If 2x - 1 equals 3x plus 4 then x equals?
2x - 1 = 3x + 4 Subtract 2x from both sides: - 1 = x + 4 Subtract 4 from both sides: -5 = x
What is 4 plus 2x minus-2x plus 1 equals 13 plus 6?
4+2x-2x+1=13+6 Combine like terms. (4+1=5; 2x-2x=0; 13+6=19) 5=19 This problem has no solution.
How would you solve 2x plus 1 equals 9?
2x+1 = 9 2x = 9-1 2x = 8 x = 4
What is the solution of -2x plus 5 equals 8 and 2x plus 2x equals 6?
5 - 2x = 8 x = -1 and 1/2 4x = 6 x = 6/4 or 3/2
Factor 2x squared - 6x plus 4 equals 0?
(2x-4)(x-1) = 0
What does x equal if 5 equals 2x plus 1?
4
