The expression:
6x2 + 7x + 12
has no factors. To demonstrate this point, let's try to find two values that we would use to break the expression down into multiple terms. We'll call them a and b. The sum of a and b should be equal to 7 (the coefficient of the middle term), and their product should be 72 (the product of the coefficients of the first and last terms:
a + b = 7
ab = 72
We can then take one of the equations and plug it into the other, reducing to a single variable:
a + 72/a = 7
And then we can try to solve for a:
∴ a - 7 = -72/a
∴ a2 - 7a = -72
∴ a2 - 7a + (7/2)2 = (7/2)2 - 72
∴ (a - 7/2)2 = (7/2)2 - 72
∴ a - 7/2 = (49/4 - 72)1/2
∴ a = (49/4 - 288/4)1/2 + 7/2
∴ a = (49 - 288)1/2 / 2 + 7/2
∴ a = (7 ± i √239) / 2
This leaves us with a pair of complex values for a and b, showing that the original expression can not be factored.
If you mean: 6x^2 +7x-3 then it is (2x+3)(3x-1) when factored
If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7
6x - 12 + 4x + 5 = 06x + 4x = 12 - 510x = 7x = 7/10
13x = -156 so x = -12
7x + 2 = 158 - 6x7x + 2 + 6x = 158 - 6x + 6x13x + 2 - 2= 158 - 213x / 13 = 156/13x = 12
If you mean: 6x^2 +7x-3 then it is (2x+3)(3x-1) when factored
If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7
6x - 12 + 4x + 5 = 06x + 4x = 12 - 510x = 7x = 7/10
6x+x=7x
X squared + 7X + 12?
7x + 7 + 6x - 9 = 13x - 2
7x + 2 = 6x + 2 if and only x = 0.
To factorize x^2 + 7x, we look for two numbers that multiply to the constant term (7) and add up to the coefficient of the x term (7). In this case, those numbers are 1 and 6. Therefore, we can rewrite the expression as x^2 + 1x + 6x + 6. Next, we factor by grouping: x(x + 1) + 6(x + 1). Finally, we factor out the common binomial factor of x + 6 to get (x + 1)(x + 6) as the fully factorized form.
13x = -156 so x = -12
7x + 2 = 158 - 6x7x + 2 + 6x = 158 - 6x + 6x13x + 2 - 2= 158 - 213x / 13 = 156/13x = 12
6x+x = 7x
7x + 9 = 6x + 17 7x - 6x = 17 -9 x = 8