Approximately 11.18
That would give a change of -10 in the x direction and +5 in the y direction. Using the Pythagorean theorem, the distance between the two points would be the square root of 125 or approximately 11.18
To find the approximate distance between the points (45) and (1013) on a coordinate grid, we can treat these as two separate points on a number line. The distance is calculated as the absolute difference between the two values: |1013 - 45| = 968. Therefore, the approximate distance between the points is 968 units.
3.61 units
The bootom of the coordinate grid
-- Square the difference between their 'x'-values. -- Square the difference between their 'y'-values. -- Add the two squares. -- Take the square-root of the sum. The result is the distance between the points.
A translation of shape on the coordinated grid moves it in the same distance and in the same direction
50
3.61 units
To find the approximate distance between the points (45) and (1013) on a coordinate grid, we can treat these as two separate points on a number line. The distance is calculated as the absolute difference between the two values: |1013 - 45| = 968. Therefore, the approximate distance between the points is 968 units.
3.61 units
3.61 units
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
Points: (-3, -4) and (-8, 1) Distance: square root of 50 or about 7.071 to three decimal places
If you mean points of (-5, 1) and (-2, 3) then using the distance formula it is the square root of 13 or about 3.6
If you mean points of (-5, 1) and (-2, 3) then using the distance formula it is the square root of 13 or about 3.61 rounded to 2 decimal places