Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
Approximately 17 feet.
Approximately 10 inches.
~26.16 units.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
It depends on 2.35m what: length of sides, diagonal, perimeter.
Approximately 17 feet.
Approximately 10 inches.
The perimeter of this square is 56.569 meters.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm
~26.16 units.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
12.73 feet
15.6977cm
It depends on 2.35m what: length of sides, diagonal, perimeter.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
The answer will depend on what information about the square you have: its perimeter, area, length of diagonal.