area = 144 square units
perimeter = 48 units
The area is 48 square inches.
3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
4.5*18 = 81 and 4.5+4.5+18+18 = a perimeter of 45 inches 3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
You need not estimate since all 4 sides of a square are congruent. The perimeter is 116 (or 29 * 4)
69
The area is 48 square inches.
3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
4.5*18 = 81 and 4.5+4.5+18+18 = a perimeter of 45 inches 3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
are 48 m bola tha tumne 48 inches likh diya...
You need not estimate since all 4 sides of a square are congruent. The perimeter is 116 (or 29 * 4)
Yes, let's take two different rectangles:The first one is 4 inches by 5 inches.The second is 2 inches by 10 inches.Both of these have an area of 20 square inches, and they are not congruent. You could also have one: 1 inch by 20 inches, 1/2 inch by 40 inches, etc.
69
If the perimeter is already measured in inches, there is nothing to convert. There are 18 inches in a perimeter of 18 inches.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.
The perimeter would be 36 inches.
The perimeter is 60 inches
24 inches is the perimeter