4m + 3m = 180 7m = 180 m = 25 5/7
Yes - as an example, a 4m by 3m by 2m prism has a volume of 4 x 3 x 2 = 24 m3, the same as a 24m by 1m by 1m prism. However, they have different surface areas. The 4m by 3m by 2m has surface area (4 x 3 x 2) + (4 x 2 x 2) + (3 x 2 x 2) = 24 + 16 + 12 = 52 m2. The 24m by 1m by 1m has surface area (24 x 1 x 2) + (24 x 1 x 2) + (1 x 1 x 2) = 48 + 48 + 2 = 98 m2.
it is 4m and 35cm that's the answer
4M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 1
36 cu m
The value of m in the equation: 4m-5 = 3m +7 is 12.
Not been doing your homework latley, huh?
0.5 + 4m = 3m - 2.5 (subtract 0.5 and 3m to both sides)0.5 - 0.5 + 4m - 3m = 3m - 3m -0.5 -2.5m = -3Check:0.5 + 4m = 3m - 2.5 (substitute -3 for m)0.5 + 4(-3) =? 3(-3) - 2.50.5 - 12 =? -9 -2.5-11.5 = -11.5 TrueThus, for m = -3 the above equation is a true statement.
4m + 3m = 180 7m = 180 m = 25 5/7
Yes - as an example, a 4m by 3m by 2m prism has a volume of 4 x 3 x 2 = 24 m3, the same as a 24m by 1m by 1m prism. However, they have different surface areas. The 4m by 3m by 2m has surface area (4 x 3 x 2) + (4 x 2 x 2) + (3 x 2 x 2) = 24 + 16 + 12 = 52 m2. The 24m by 1m by 1m has surface area (24 x 1 x 2) + (24 x 1 x 2) + (1 x 1 x 2) = 48 + 48 + 2 = 98 m2.
it is 4m and 35cm that's the answer
4M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 1
"3m feet" and "4m feet" are unknown terms, therefore there is not enough data to answer the question. "3m" would normally mean 3 meters. but if in terms it could be 12m^2 feet
96m3
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
i think $3m or $4m
It is: 4m+5