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Q: What is the area of 5ft 6ft and 10ft?
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What is the area of a figure that has 6ft 10ft 5ft?

Assuming the shape is a triangle, the area is 11.40 sq ft, approx.


What is the area of a figure that has 6ft 10ft 5ft 3ft?

It is not possible to determine the area of a quadrilateral given only the length of its four sides.


What is the area of 6cm and 2cm?

12cm is the answer


What is the area of a square that is 6ft by 5ft?

The area of square is : 36.0


What is the area of a figure that has 6ft 10ft 5ft 3ft .use 3.14?

Not enough information. You need to know what sort of figure you are talking about - for example a rectangle, an ellipse, the surface of a rectangular block, etc.


If a room is 6ft by 10ft how many square feet is that?

The area is the product of (Length) times (Width)6ft by 10ft = (6 x 10) = 60 square feet.


How many sq. ft does 6ft. by 10ft. equal?

The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.


What is 6ft by 5ft?

a 6ft by 5ft rectangle is a 6 feet by 5 feet rectangle.


What is 6ft by 5ft rectangle?

a 6ft by 5ft rectangle is a 6 feet by 5 feet rectangle.


How tall are the boys from the wanted?

Nathan - 5ft 9 Max - 5ft 9.5 Tom - 5ft 10 Jay -6ft Siva - 6ft 1


How tall are the boys in the wanted?

The Wanted (heights) Nathan - 5ft 9 Max - 5ft 9.5 Tom - 5ft 10 Jay -6ft Siva - 6ft 1


What is the area of 10Ft 3Ft 6Ft and 5Ft?

It is not possible to provide an answer. Four linear measurements suggest that the figure is a quadrilateral of some sort. Unfortunately, information about the lengths of the sides is not enough to uniquely identify the shape and so the area cannot be determined. In order to see why the area cannot be determined, consider a rectangle with sides of 1 cm, 2cm, 1 cm and 2 cm. Clearly, its area is 1*2 = 2 cm2. However, the rectangle can be "distorted" into a parallelogram, with the same sides, but whose vertical height (and so its area) is reduced to 0!