Not enough information. You need to know what sort of figure you are talking about - for example a rectangle, an ellipse, the surface of a rectangular block, etc.
a 6ft by 5ft rectangle is a 6 feet by 5 feet rectangle.
6ft 4in minus 3ft 8in
Rectangle area, square metre = (rectangle length, metre) x (rectangle width, metre)
10ft x 6ft = 60 sq ft = 5.57 sq metres, approx.
Assuming the shape is a triangle, the area is 11.40 sq ft, approx.
It is not possible to determine the area of a quadrilateral given only the length of its four sides.
12cm is the answer
The area of square is : 36.0
The area is the product of (Length) times (Width)6ft by 10ft = (6 x 10) = 60 square feet.
Not enough information. You need to know what sort of figure you are talking about - for example a rectangle, an ellipse, the surface of a rectangular block, etc.
The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.
a 6ft by 5ft rectangle is a 6 feet by 5 feet rectangle.
a 6ft by 5ft rectangle is a 6 feet by 5 feet rectangle.
Nathan - 5ft 9 Max - 5ft 9.5 Tom - 5ft 10 Jay -6ft Siva - 6ft 1
The Wanted (heights) Nathan - 5ft 9 Max - 5ft 9.5 Tom - 5ft 10 Jay -6ft Siva - 6ft 1
It is not possible to provide an answer. Four linear measurements suggest that the figure is a quadrilateral of some sort. Unfortunately, information about the lengths of the sides is not enough to uniquely identify the shape and so the area cannot be determined. In order to see why the area cannot be determined, consider a rectangle with sides of 1 cm, 2cm, 1 cm and 2 cm. Clearly, its area is 1*2 = 2 cm2. However, the rectangle can be "distorted" into a parallelogram, with the same sides, but whose vertical height (and so its area) is reduced to 0!