Area of a triangle in square units = 0.5*base*height
Two unspecified measures are not enough to determine the area of a triangle.
No, you cannot construct a triangle with side lengths 2 yd, 9 yd, and 10 yd. This is because the sum of the lengths of the two shorter sides (2 yd + 9 yd = 11 yd) must be greater than the length of the longest side (10 yd) to satisfy the triangle inequality theorem. Since 11 yd is greater than 10 yd, these lengths do not form a triangle.
Area = 1/2*b*h104 yd2 = 1/2(13 yd)hmultiply through by 2208 = 13h208/13 = hHeight = 16 yards=============
No, Yes, No.
A mile contains 1760 yards. Therefore, 40 yd/1760(yd/mi) = 0.0227 miles. An hour contains 60 minutes of 60 seconds each. Therefore, 6.5 seconds = 6.5/(60 X 60) = 0.00181 hour. 0.0227 miles/0.00181 = 13 mph, to the justified number of significant digits.
Two unspecified measures are not enough to determine the area of a triangle.
Area = 12 sqyds
76.4 square yards
Need to know the triangle's height to tell.
Area = 1/2*b*h104 yd2 = 1/2(13 yd)hmultiply through by 2208 = 13h208/13 = hHeight = 16 yards=============
No, Yes, No.
A mile contains 1760 yards. Therefore, 40 yd/1760(yd/mi) = 0.0227 miles. An hour contains 60 minutes of 60 seconds each. Therefore, 6.5 seconds = 6.5/(60 X 60) = 0.00181 hour. 0.0227 miles/0.00181 = 13 mph, to the justified number of significant digits.
0.5*base*height = 0.5*2*3 = 3 square yards.
No because the given dimension do not comply with Pythagoras' theorem for a right angle triangle
Running 40 yards in 4.2 seconds is equal to running 19.5 MPH.
V = ( area ) ( depth ) = ( A ) ( d ) A = ( 40 acres ) ( 43560 ft^2 / acre ) ( 1 yd^2 / 9 ft^2 ) A = 193600 yd^2 d = V / A d = ( 96,000 yd^3 ) / ( 193600 yd^2 ) d = 0.4959 yd d = ( 0.4959 yd ) ( 3 ft / yd ) = 1.468 ft = 17.85 in <------
174 sq. yards