Two unspecified measures are not enough to determine the area of a triangle.
Area = 1/2*b*h104 yd2 = 1/2(13 yd)hmultiply through by 2208 = 13h208/13 = hHeight = 16 yards=============
No, Yes, No.
A mile contains 1760 yards. Therefore, 40 yd/1760(yd/mi) = 0.0227 miles. An hour contains 60 minutes of 60 seconds each. Therefore, 6.5 seconds = 6.5/(60 X 60) = 0.00181 hour. 0.0227 miles/0.00181 = 13 mph, to the justified number of significant digits.
No because the given dimension do not comply with Pythagoras' theorem for a right angle triangle
Two unspecified measures are not enough to determine the area of a triangle.
Area = 12 sqyds
76.4 square yards
Need to know the triangle's height to tell.
Area = 1/2*b*h104 yd2 = 1/2(13 yd)hmultiply through by 2208 = 13h208/13 = hHeight = 16 yards=============
No, Yes, No.
0.5*base*height = 0.5*2*3 = 3 square yards.
A mile contains 1760 yards. Therefore, 40 yd/1760(yd/mi) = 0.0227 miles. An hour contains 60 minutes of 60 seconds each. Therefore, 6.5 seconds = 6.5/(60 X 60) = 0.00181 hour. 0.0227 miles/0.00181 = 13 mph, to the justified number of significant digits.
No because the given dimension do not comply with Pythagoras' theorem for a right angle triangle
Running 40 yards in 4.2 seconds is equal to running 19.5 MPH.
V = ( area ) ( depth ) = ( A ) ( d ) A = ( 40 acres ) ( 43560 ft^2 / acre ) ( 1 yd^2 / 9 ft^2 ) A = 193600 yd^2 d = V / A d = ( 96,000 yd^3 ) / ( 193600 yd^2 ) d = 0.4959 yd d = ( 0.4959 yd ) ( 3 ft / yd ) = 1.468 ft = 17.85 in <------
174 sq. yards