Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.
Area = L*W Area = 14* (5x-3) Area = 60x-42
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
A = Area l = length w = width A = (l)(w) Ex: L = 5 in. W = 2 in. A = ? A = l(w) A = 5(2) A = 10 in2
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
Ain W Zain's population is 2,000.
The area of Ain is 5,762 square kilometers.
The area of Ain Tarik is 178 square kilometers.
The area of Ain Saadeh is 548 square kilometers.
The area of Ain Dara temple is 600.0 square meters.
The area of Chazey-sur-Ain is 21.95 square kilometers.
The area of Serrières-sur-Ain is 8,180,000.0 square meters.
The area of Charnoz-sur-Ain is 6,620,000.0 square meters.
The area of Neuville-sur-Ain is 19.79 square kilometers.
The area of Ain el Safssaf is 1,770,000.0 square meters.
The area of Villette-sur-Ain is 19.38 square kilometers.
The area of Ain Tarik District is 322 square kilometers.