diameter = 198/pi = 63.02535746 cm
The area of Buroz is 198 square kilometers.
There are 0.0254 metres in one inch. Therefore, 198 inches is equal to 198 x 0.0254 = 5.0292 metres.
L=L(initial)[1+C(al)]*T =1.184cm I can't figure out the second one either
Area = 18*11 = 198 square inches
Oh, dude, you just gotta remember your basic math for this one. The circumference of a circle is π times the diameter, so if the diameter is 63mm, just plug that into the formula and you get 63π mm or approximately 197.92mm. Easy peasy, right?
diameter = 198/pi = 63.02535746 cm
To find the area of a square rod in square inches, you would square the length of one side of the rod, which is typically given in inches. So if the rod has sides of 1 inch each, the area would be 1 inch x 1 inch = 1 square inch. If the sides are 2 inches each, the area would be 2 inches x 2 inches = 4 square inches, and so on.
There are 2.54 centimetres in one inch. Therefore, rounded to two decimal places, 198 centimetres is equal to 198/2.54 = 77.95 inches.
The area of Garbakoïra is 198 square kilometers.
The area of Dzidzantún is 198 square kilometers.
The area of Buroz is 198 square kilometers.
The area of Osisioma Ngwa is 198 square kilometers.
Amounts of parts: (66*48)/16 = 198 square sheets
There are 198 inches in one rod. There are 2.54 centimetres in one inch. Therefore, one rod is equal to 198 x 2.54 = 502.92 centimetres.
sounds good to me...
A rod is a unit of measurement equal to 16.5 feet. This is equal to 16.5 x 12 = 198 inches. There are 2.54 centimetres in one inch. Therefore, 198 inches is equal to 2.54 x 198 = 502.92 centimetres.